How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?

4.16L

Explanation:

From the question given, we obtained the following dа ta:

Molarity = 0.225 M

Number of mole of KI = 0.935mole

Volume = ?

Molarity = mole / Volume

Volume = mole / Molarity

Volume = 0.935/0.225

Volume = 4.16L

Therefore, 4.16L of KI is needed.