To what pressure would you have to compress 48.0 L

of oxygen gas at 99.3 kPa in order to reduce its vol-

ume to 16.0 L?

Question

Chemistry

Shuttershy

16 September, 01:44

To what pressure would you have to compress 48.0 L

of oxygen gas at 99.3 kPa in order to reduce its vol-

ume to 16.0 L?

+3

Answers (1)

Know the Answer?

Jovany Carson · Answer 1

298 kPa

Explanation:

Data Given:

initial Volume of oxygen V1 = 48.0 L

Final Volume of oxygen V2 = 16.0 L

initial pressure of oxygen P1 = 99.3 kPa

initial Pressure of oxygen P2=?

Solution:

The Boyle's law formula will be applicable here at constant temperature

Boyle's law formula

P1V1 = P2V2

As we have to find final pressure so rearrange the equation

P2 = P1V1 / V2 ... (1)

Put values in Equation 1

P2 = 99.3 kPa x 48 L / 16 L

P2 = 298 kPa

So the final pressure will be 298 kPa

To what pressure would you have to compress 48.0 Lof oxygen gas at 99.3 kPa in order to reduce its vol-ume to 16.0 L?

To what pressure would you have to compress 48.0 L

of oxygen gas at 99.3 kPa in order to reduce its vol-

ume to 16.0 L?