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6 June, 01:20

so they are asking me to find the empirical formula for a compound that is 7.70% carbon and 92.3% chlorine. Can you show me step by step how to solve this step

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  1. 6 June, 01:34
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    Empirical formula is CCl₄

    Explanation:

    Given dа ta:

    Percentage of carbon = 7.70%

    Percentage of chlorine = 92.3%

    Empirical formula = ?

    Solution:

    Number of gram atoms of Cl = 92.3 / 35.5 = 2.6

    Number of gram atoms of C = 7.70 / 12 = 0.64

    Atomic ratio:

    C : Cl

    0.64/0.64 : 2.6/0.64

    1 : 4

    C : Cl = 1 : 4

    Empirical formula is CCl₄.
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