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21 November, 23:18

You fill a balloon with helium gas to a volume of 2.68 L at 23*Cand 789 mmHg. Then you release the balloon. What would be thevolume of helium if its pressure changed to 556 mmHg but thetemperature remained unchanged?

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  1. 22 November, 00:06
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    The volume of helium will be 3.80 L

    Explanation:

    Step 1: Data given

    Initial volume of the balloon = 2.68 L

    Initial temperature of the balloon = 23°C = 296 K

    Final temperature of the balloon = 23°C = 296 K

    Initial pressure of the balloon = 789 mmHg

    Final pressure of the balloon = 556 mmHg

    Step 2: Calculate final volume

    (P1*V1) / T1 = (P2V2) / T2

    (789 * 2.68) / 296 = (556*V2) / 296

    V2 = (789*2.68) / 556

    V2 = 3.80 L

    The volume of helium will be 3.80 L
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