How many moles of a gas at 104°C would occupy a volume of 6.8

L at a pressure of 270 mm Hg?

0.079mole

Explanation:

From the question given, we obtained the following dа ta:

T = 104°C = 104 + 273 = 377K

V = 6.8L

P = 270 mmHg

Recall: 760mmHg = 1atm

Therefore, 270 mmHg = 270/760 = 0.36atm

R = 0.082atm. L/Kmol

n = ?

Using the ideal gas equation:

PV = nRT

We can easily obtain the number of mole as follow:

PV = nRT

n = PV / RT

n = 0.36 x 6.8 / 0.082 x 377

n = 0.079mole

The number of mole of the gas is 0.079mole