What was the total number of calories lost when 10 grams of water at 80c is cooled to 60c?

Q = - 200 cal

Explanation:

Given dа ta:

Calories lost = ?

Mass of water = 10 g

Initial temperature = 80°C

Final temperature = 60°C

Solution:

Specific heat capacity of water is 1 cal/g.°C

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 60°C - 80°C

ΔT = - 20°C

Q = m. c. ΔT

Q = 10 g. 1 cal/g.°C. - 20°C

Q = - 200 cal