How many grams of Cl2 are in 1.20 x 1024 Cl atoms?

70.906 g

Explanation:

We are given;

Atoms of Chlorine = 1.2 * 10^24 atoms

We are required to calculate the mass of Chlorine

We know that 1 mole of an element contains atoms equivalent to the Avogadro's number, 6.022 * 10^23. That is, 1 mole of an element = 6.022 * 10^23 atoms Therefore; 1 mole of Chlorine = 6.022 * 10^23 atoms

But since Chlorine gas is a molecule;

1 mole of Chlorine gas = 2 * 6.022 * 10^23 atoms

But, molar mass of Chlorine gas = 70.906 g/mol

Then;

70.906 g Of chlorine gas = 2 * 6.022 * 10^23 atoms

= 1.20 * 10^24 atoms

Thus;

For 1.2 * 10^24 atoms;

= (70.906 g/mol * 1.2 * 10^24 atoms) : (1.20 * 10^24 atoms)

= 70.906 g

Therefore, 1.20 * 10^24 atoms of chlorine contains a mass of 70.906 g

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