If 4.55 mol of calcium carbide (CaC2) reacts with an excess of water, how many moles of acetylene (C2H2), a gas used in welding, will be produced?

There will be produced 4.55 moles C2H2 (this is 118.48 grams)

Explanation:

Step 1: Data given

Number of moles CaC2 = 4.55 moles

water is in excess

Molar mass of CaC2 = 64.1 g/mol

Molar mass of acetylene = 26.04 g/mol

Step 2: The balanced equation

CaC2 + 2H2O → C2H2 + Ca (OH) 2

Step 3: Calculate moles of C2H2

For 1 mol CaC2 we need 2 moles of H2O to produce 1 mol of C2H2 and 1 mol of Ca (OH) 2

For 4.55 moles of CaC2 we'll have 4.55 moles C2H2

Mass C2H2 = 4.55 moles C2H2 * 26.04 g/mol = 118.48 grams

There will be produced 4.55 moles C2H2 (this is 118.48 grams)