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4 April, 13:01

What is the empirical formula of a molecule containing 65.5% carbon, 5.5% hydrogen, and 29.0% oxygen?

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  1. 4 April, 14:22
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    The empirical formula is C3H3O

    Explanation:

    Step 1: Data given

    Suppose the mass of the molecule = 100 grams

    The molecule contains:

    65.5 % Carbon = 65.5 grams

    5.5 % Hydrogen = 5.5 grams

    29.0% Oxygen = 29.0 grams

    Molar mass of C = 12 g/mol

    Molar mass of H = 1.01 g/mol

    Molar mass of O = 16 g/mol

    Step 2: Calculate moles

    Moles = mass / molar mass

    Moles C = 65.5 grams / 12 g/mol = 5.46 moles

    Moles H = 5.5 / 1.01 g/mol = 5.45 moles

    Moles O = 29.0 grams / 16 g/mol = 1.8125 moles

    Step 3: Calculate mol ratio

    We divide by the smallest amount of moles

    C: 5.46 / 1.8125 = 3

    H = 5.45 / 1.8125 = 3

    O = 1.8125/1.8125 = 1

    The empirical formula is C3H3O
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