Write the net ionic equation for the reaction of aqueous solutions of silver nitrate and lithium bromide. (Include states-of-matter under the given conditions in your answer. Use the lowest possible whole number coefficients.)

Ag⁺ (aq) + Br⁻ (aq) ⇒ AgBr (s)

Explanation:

The reaction between silver nitrate and lithium bromide is as follows:

AgNO₃ (aq) + LiBr (aq) ⇒ AgBr (s) + LiNO₃ (aq)

The aqueous compounds will dissociate into their ions, so the reaction may be rewritten as:

Ag⁺ (aq) + NO₃⁻ (aq) + Li⁺ (aq) + Br⁻ (aq) ⇒ AgBr (s) + Li⁺ (aq) + NO₃⁻ (aq)

In order to form the net ionic equation, we remove from the reaction any ions that did not undergo a chemical change (ions that are exactly the same on the reactants side and on the products side). These ions are referred to as spectator ions. The spectator ions are NO₃⁻, Li⁺, and Br⁻. The net ionic equation is then:

Ag⁺ (aq) + Br⁻ (aq) ⇒ AgBr (s)