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7 January, 17:21

Suppose that 0.25 mole of gas C was added to

the mixture without changing the total pressure of

the mixture.

What is the partial pressure of C?

+1
Answers (1)
  1. 7 January, 20:05
    0
    Pi = 0.25[P (TTL) / n (TTL) ]

    Explanation:

    Let Total Pressure = P (TTL) and Total moles = n (TTL) = > n (i) / n (TTL) = P (i) / P (TTL)

    Given n (i) = 0.25 = > Pi = 0.25[P (TTL) / n (TTL) ]
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