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23 March, 18:20

A mixture of three gases has a pressure at 298 K of 1380 mm Hg. The mixture is analysed and is found to contain 1.27 mol CO2, 3.04 mol CO, and 1.50 mol Ar. What is the partial pressure of Ar?

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  1. 23 March, 21:57
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    The partial pressure of Ar is 356.3 mmHg

    Explanation:

    The concept of the molar fraction can be applied to calculate the partial pressure of a gas, in a mixture where the molar fraction is equal to the gas pressure, over the total pressure.

    PCO2 / Total pressure = n° moles CO2 / Total moles

    So we have the total pressure, the moles of Ar and the total moles

    The sum of moles is moles Ar + moles CO + moles CO₂ =

    1.27 + 3.04 + 1.5 = 5.81

    1,5 moles of Ar / 5.81 moles = Partial pressure Ar / Total Pressure

    1,5 moles of Ar / 5.81 moles = Partial pressure Ar / 1380mmHg

    (1,5 moles of Ar / 5.81 moles). 1380mmHg = Partial Pressure Ar

    356,3 mmHg = Partial Pressure Ar
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