2 NaOH + H2SO4 → 2 H, 0 + Na S04

How many grams of sodium sulfate will be formed if you start with 200 grams of sodium

hydroxide and you have an excess of sulfuric acid? I am having difficulties finding the grams.

200 grams of sodium hydroxide produce 595 grams of sodium sulfate if we have an excess of sulphuric acid

Explanation:

2 NaOH + H2SO4 → 2 H20 + Na S04

From the above chemical equation we can state that

2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate.

Now if we start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid then the amount in grams of sodium sulfate will be formed

2 moles of sodium hydroxide produce 1 mole of sodium sulfate.

In term of mass, we can say that

40 grams of sodium hydroxide produce 119grams of sodium sulfate

1 grams of sodium hydroxide produce (119/40) grams of sodium sulfate

then 200 grams of sodium hydroxide produce ((119*200) / 40) grams of sodium sulfate

or 200 grams of sodium hydroxide produce 595 grams of sodium sulfate