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12 November, 12:17

The volume of a gas at STP is 7.30 L. What is the quantity of gas in this sample?

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Answers (2)
  1. 12 November, 13:52
    0
    0.326 moles

    Explanation:

    We are given;

    Volume of a gas at STP as 7.30 L

    We are supposed to determine the quantity of the gas sample;

    We need to know that 1 mole of a gas occupies a volume of 22.4 L at standard temperature and pressure. On the other hand, at room temperature and pressure, 1 mole of a gas will occupy a volume of 24 L

    In this case;

    1 mole = 22.4 L

    Therefore;

    Moles = Volume : Molar gas volume at STP

    Therefore,

    Moles of the gas sample = 7.30 L : 22.4 L

    = 0.326 moles

    Therefore, the quantity of the gas sample is 0.326 moles
  2. 12 November, 15:55
    0
    The quantity of gas is 0.33 mol.

    Explanation:

    Given dа ta:

    Volume of gas = 7.30 L

    Pressure of gas = 1 atm

    Temperature of gas = 273 K

    Amount of gas = ?

    Solution:

    PV = nRT

    n = PV / RT

    n = 1 atm. 7.30 L / 0.0821 atm. L. mol⁻¹. K⁻¹ * 273 K

    n = 7.30 atm. L / 22.4 atm. L. mol⁻¹

    n = 0.33 mol
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