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16 March, 21:39

If trial 2 generated 37.49 mL of hydrogen gas at 22.00oC, use 714.4 pressure difference to determine what this volume corresponds to at STP.

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  1. 16 March, 23:31
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    V₂ = 24785.5 mL.

    Explanation:

    Given dа ta:

    Initial volume of hydrogen gas = 37.49 mL

    Initial temperature = 22.0°C (22 + 273 = 295 K)

    Initial pressure = 714.4 atm

    Final temperature = 273 K

    Final pressure = 1 atm

    Final volume of hydrogen gas = ?

    Solution;

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    V₂ = P₁V₁T₂ / T₁ P₂

    V₂ = 714.4 atm * 37.49 mL * 273 K / 295 K * 1 atm

    V₂ = 7311719.7 mL / 295

    V₂ = 24785.5 mL.
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