A chemist began with 61.5 grams of naclo3. After collecting and drying the product, 30 grams of nacl was obtained. what was the theoretical yield of nacl

Question

Chemistry

Cochran

7 February, 07:38

A chemist began with 61.5 grams of naclo3. After collecting and drying the product, 30 grams of nacl was obtained. what was the theoretical yield of nacl

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Answers (1)

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Pitts · Answer 1

33.78 g

Explanation:

NaClO3 decomposes to NaCl and O2 by this reaction:

2NaClO3 - -> 2NaCl + 3O2

Let's determines the mole of chlorate we used (mass / molar mass)

61.5 g / 106.45 g/mol = 0.578 moles.

Ratio is 2:2, so x amount of chlorate will produce x amount of chloride. In conclussion we made 0.578 moles of NaCl from 0.578 moles of chlorate. Let's convert the moles to mass:

0.578 mol. 58.45g/1mol = 33.78 g

That is the theoretical yield of NaCl.