Na + Br2 - -> NaBr Calculate how many grams of NaBr may be produced from 5.00 grams of solid sodium metal when combined with unlimited Bromine gas.

22.39g of NaBr

Explanation:

First let us write a balanced equation for the reaction. This is illustrated below:

2Na + Br2 - > 2NaBr

Molar Mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar Mass of NaBr = 23 + 80 = 103g/mol

Mass of NaBr from the balanced equation = 2 x 103 = 206g

From the equation,

46g of Na produced 206g NaBr.

Therefore, 5g of Na will produce = (5 x 206) / 46 = 22.39g of NaBr