A student dissolves of potassium chloride in of water in a well-insulated open cup. He then observes the temperature of the water fall from to over the course of minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction: () () () You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to 2 significant digits. Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction. Is this reaction exothermic, endothermic, or neither. Calculate the reaction enthalpy AW per mole of NaOH

Question

Chemistry

Giancarlo Sparks

29 July, 23:03

A student dissolves of potassium chloride in of water in a well-insulated open cup. He then observes the temperature of the water fall from to over the course of minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction: () () () You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to 2 significant digits. Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction. Is this reaction exothermic, endothermic, or neither. Calculate the reaction enthalpy AW per mole of NaOH

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Answers (1)

Know the Answer?

Greyson Barnes · Answer 1

1) Endothermic

2) Heat absorbed by reaction = 2511.6J

3) ΔH_rxn = 18.2 kJ / mol

Explanation:

Mass of KCl = 10.3 g

Moles of KCl = mass of KCl / molar mass of KCl

= 10.3 g / 74.5513 g/mol

=0.138 mol

Mass of water, m = 200 g

Specific heat of water, C = 4.186 Jg^-1°C^-1

T_initial = 22.0C

T_final = 19.0°C

ΔT = T_final - T_initial

=19.0°C - 22.0°C

= - 3.0°C

Heat absorbed = Heat released

q_rxn = -q_water

so,

q_water = m CΔT

substitute

q_water = 200g * 4.186J g^-1 °C^-1 * (-3.0°C)

= - 2511.6J

Heat absorbed by reaction = 2511.6J

q_rxn = - q_water = 2511.6J

ΔH_rxn = q_rxn / moles of KCl

=2511.6J / 0.138 mol

ΔH_rxn = 18.2kJ / mol

The reaction is a endothermic reaction.