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28 August, 08:23

the volume of air in a diving bell changes as it descends into deep water. if the air in a diving bell occupies 9.50 L at 1.02 atm and 20.1 c what will be the volume of the air at 1.55 atm and 15.0 c

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  1. 28 August, 11:45
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    V₂ = 6.14 L

    Explanation:

    Given dа ta:

    Initial volume = 9.5 L

    Initial pressure = 1.02 atm

    Initial temperature = 20.1 °C (20.1 + 273 = 293.1 K)

    Final temperature = 15°C (15+273 = 288 K)

    Final volume = ?

    Final pressure = 1.55 atm

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Solution:

    P₁V₁/T₁ = P₂V₂/T₂

    V₂ = P₁V₁T₂/T₁ P₂

    V₂ = 1.02 atm * 9.50 L * 288 K / 293.1 K * 1.55 atm

    V₂ = 2790.72 atm. L. K / 454.305 K. atm

    V₂ = 6.14 L
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