Ask Question
22 June, 20:19

How many grams of sulfur (S8S8) must be dissolved in 100.0 g naphthalene (C10H8C10H8) to make a 0.11 mm solution

+4
Answers (1)
  1. 22 June, 23:11
    0
    5.64x10⁻³ g of S₈S₈

    Explanation:

    We consider mm as milimolal

    Milimolal = molal. 1000

    Molal are the moles of solute contained in 1kg of solvent.

    Solute → Sulfur (S₈S₈)

    Solvent → naphthalene

    0.11 mm / 1000 = 1.1x10⁻⁴ molal

    moles of solute / kg of solvent = 1.1x10⁻⁴ molal

    moles of solute / 0.1 kg of solvent = 1.1x10⁻⁴ molal

    moles of solute = 1.1x10⁻⁴ m/kg. 0.1kg → 1.1ₓ10⁻⁵ moles

    Molar mass S₈S₈ = 512.96 g/m

    1.1ₓ10⁻⁵ mol. 512.96 g/m = 5.64x10⁻³ g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many grams of sulfur (S8S8) must be dissolved in 100.0 g naphthalene (C10H8C10H8) to make a 0.11 mm solution ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers