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14 March, 10:19

Theoretically, how much zinc [At. Wt. = 65.41] in grams would be needed to produce 500.00 grams of copper metal from any soluble copper (II) salt?

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  1. 14 March, 13:05
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    514.65 g of Zn

    Explanation:

    Zinc metal reacts with copper ions in a salt of copper to form copper metal and zinc (ii) salt.

    The equation for the reaction is;

    Zn (s) + Cu²⁺ (aq) → Zn²⁺ (aq) + Cu (s)

    we are required to calculate the mass of Zinc needed

    Step 1: Number of moles of copper

    The mass of copper metal produced is 500.0 grams

    We can get the number of moles of copper,

    Molar mass of copper = 63.55 g/mol

    But; Number of moles = Mass : Molar mass

    Therefore;

    Moles of copper = 500.0 g : 63.55 g/mol

    = 7.868 moles

    Step 2: Moles of Zinc

    From the reaction 1 mole of Zinc metal reacts with a salt of copper (ii) to produce 1 mole of copper.

    Therefore, the ratio of Zn : Cu is 1 : 1

    Hence;

    Moles of zinc will be 7.868 moles

    Step 3: Mass of Zinc metal

    Moles of Zn = 7.868 moles

    Molar mass of Zn = 65.41 g/mol

    But; Mass = number of moles * molar mass

    Thus;

    Mass of Zn = 7.868 moles * 65.41 g/mol

    = 514.65 g

    Therefore, the mass of Zn metal needed is 514.65 g
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