Which relationship or statement best describes delta s for the following reaction:

2H2S (g) + 3O2 (g) - -> 2H2O (g)

a) Delta S = 0

b) Delta S < 0

c) Delta S> 0

d) Delta S = Delta H |T

e) More information is needed to make a reasonable prediction.

b) Delta S < 0

Explanation:

The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn (g) = n (g, products) - n (g, reactants).

If Δn (g) > 0, the entropy increases (ΔS > 0). If Δn (g) < 0, the entropy decreases (ΔS < 0). If Δn (g) = 0, there is little or no change in the entropy

Let's consider the following equation.

2 H₂S (g) + 3 O₂ (g) → 2 H₂O (g)

Δn (g) = 2 - 5 = - 3. Since Δn (g) < 0, the entropy decreases and ΔS < 0.