Ask Question
18 August, 15:43

Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.

What is the total pressure inside the cylinder? 6.7 atm

What is the mole fraction of N2 in the mixture? 0.52 atm

2 equations: First, P subscript T equals P subscript 1 plus P subscript 2 plus P subscript 3 plus ellipses plus P subscript n. Second: StartFraction P subscript a over P subscript T EndFraction equals StartFraction n subscript a over N subscript T EndFraction.

What is the mole fraction of O2 in the mixture? atm

What is the mole fraction of Ar in the mixture? atm

+3
Answers (2)
  1. 18 August, 15:54
    0
    This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:

    Explanation:

    P = 3.00 atm + 2.80 atm + 0.25 atm + 0.15 atm

    P = 6.8 atm

    3.5 atm = x (6.8 atm)

    x = 0.51
  2. 18 August, 19:05
    0
    A. 6.7 atm

    B. 0.522

    C. 0.418

    D. 0.037

    Explanation:

    Dalton's law of partial pressure states that in a micture of non-reacting gases, the total pressure exerted by the mixture os the sum of their individual partial pressure

    Mathematically, this can be written as:

    PT = P1 + P2 + P3 + ... + Pn

    Where PT is the total partial pressure

    P1, P2, P3, ..., Pn is the individual partial pressure of the gases that form the mixture.

    A. The gases in this mixture is O2, Ar, N2 and He

    O2 = 2.8 atm

    Ar = 0.25 atm

    N2 = 3.5 atm

    He = 0.15 atm

    PT = PO2 + PAr + PN2 + PHe

    = (2.8 + 0.25 + 3.5 + 0.15) atm

    =6.7 atm

    B. Mole fraction of N2

    P1 = x1*PT

    PT = x1*PT + x2*PT + x3*PT + ... + xnPn

    Mole fraction, xn = Pn/PT

    xN2 = 3.5/6.7

    = 0.522

    C. Mole fraction of O2

    xO2 = 2.8/6.7

    = 0.418

    D. Mole fraction of Ar

    xAr = 0.25/6.7

    = 0.037
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He. What is the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers