If 18.1 mLmL of 0.800 M HClM HCl solution are needed to neutralize 5.00 mLmL of a household ammonia solution, what is the molar concentration of the ammonia?

Concentration of ammonia = 3M

Explanation:

The reaction for the question is a neutralization reaction between HCl and NH₃

The chemical equation for the reaction is given as

HCl + NH₃ → NH₄CL

1 : 1 1

Volume of HCl = 18.1ml = 0.0181L

Volume of NH₃ = 5ml = 0.005L

Molar concentration of HCl=0.8M

Molar Concentration of NH₃ = ?

Number of moles (n) = Molar concentration * Volume

n = C * V

n of HCL = 0.8 * 0.0181

n = 0.01448moles

Since mole ration for the reaction from the balanced equation above is 1:1,

n of NH₃ = 0.01448

molar concentration (C) of NH₃ = n/v

C of NH₃ = 0.01448/0.005

C of NH₃=2.896

C OF NH₃ = 3M