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4 June, 08:05

How many milliliters of 12.0 M hydrochloric acid contain 3.646 g of HCl (36.46 g/mol) ?

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  1. 4 June, 08:20
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    8.3ml of 12M HCl contains 3.646 grams HCl

    Explanation:

    moles HCl = Molarity X Volume = > Volume (Liters) = moles HCl/Molarity

    Vol (L) = (3.646g/36.46g/mole) / 12M = 0.0083Liter x 1000ml/L = 8.3ml
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