How many atoms are in 36.1 g of boron

The answer is 2.011 * 10^24

Explanation:

Looking for atoms in boron,

Molar mass of B = 10.81g/mol

There is 36.1g of B,.

Using avogadro constant = 6.023 * 10^23

36.1g of B = 6.023 * 10^23/10.81 * 36.1g

That is, 6.023*10^23 divided by 10.81 multiplied by 36.1g

From this calculation, we get

36.1g of boron = 2.011 * 10^24atoms.