A team adds 5.00 mL of exhibit water to an empty beaker using a volumetric pipette. What is the density of the exhibit water if the empty beaker weighed 18.926g and the beaker weighed 24.041g after adding the water sample?

Question

Chemistry

Aubrey Norton

20 March, 06:50

A team adds 5.00 mL of exhibit water to an empty beaker using a volumetric pipette. What is the density of the exhibit water if the empty beaker weighed 18.926g and the beaker weighed 24.041g after adding the water sample?

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Answers (1)

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Isabel · Answer 1

d = 1.023 g/mL

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL, kg/L

Formula:

D=m/v

D = density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given dа ta:

Volume of water = 5.00 mL

Weight of empty beaker = 18.926 g

Weight of beaker with water = 24.041 g

Density of water = ?

Solution:

First of all we will calculate the mass of water.

Mass of water = mass of beaker with water - mass of beaker

Mass of water = 24.041 g - 18.926 g

Mass of water = 5.115 g

Density:

d = m/v

d = 5.115 g / 5.00 mL

d = 1.023 g/mL