A sample of neon gas has a volume of 2.85 L and a temperature of 15 °C, under a constant pressure. What is the new temperature (in °C), if the volume is decreased to 1.45 L?

The answer to your question is T2 = 146.52 °K

Explanation:

Data

Volume 1 = 2.85 L

Temperature 1 = 15°C

Temperature 2 = ?

Volume 2 = 1.45 L

Process

1. - Use Charles' law to solve this problem

V1/T1 = V2/T2

2. - Convert temperature to °K

T1 = 15 + 273 = 288°K

T2 = ?

3. - Substitution

2.85/288 = 1.45/T2

Solve for T2

T2 = 1.45 (288) / 2.85

Simplification

T2 = 417.6/2.85

Result

T2 = 146.52 °K