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8 September, 10:52

Balance the following Equation:

___Zn + ___HCl - -> ___ZnCl2 + ___H2

50g of zinc are reacted with 50g of hydrogen chloride. Calculate the amount of hydrogen made.

A: 0.765g

B: 1.5g

C: 1.4 g

D: 0.685g

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Answers (1)
  1. 8 September, 14:51
    0
    The amount of hydrogen gas made is 1.4 grams (option C is correct)

    Explanation:

    Step 1: Data given

    Mass of Zinc (Zn) = 50.0 grams

    Mass of Hydrogen chloride (HCl) = 50.0 grams

    atomic mass Zn = 65.38 g/mol

    Molar mass HCl = 36.46 g/mol

    Step 2: The balanced equation

    Zn + 2HCl → ZnCl2 + H2

    step 3: Calculate moles

    Moles = mass / molar mass

    Moles Zn = 50.0 grams / 65.38 g/mol

    Moles Zn = 0.764 moles

    Moles HCl = 50.0 grams / 36.46 g/mol

    Moles HCl = 1.37 moles

    Step 4: Calculate limiting reactant

    For 1 mol n we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

    HCl is the limiting reactant. It will completely be consumed (1.37 moles)

    Zn is in excess. There will react 1.37/2 = 0.685 moles

    There will remain 0.764 - 0.685 = 0.079 moles

    Step 5: Calculate moles H2

    For 1 mol n we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

    For 1.37 moles HCl we'll have 1.37/2 = 0.685 moles H2

    Step 6: Calculate mass H2

    Mass H2 = 0.685 moles * 2.02 g/mol

    MAss H2 = 1.38 grams ≈ 1.4 grams

    The amount of hydrogen gas made is 1.4 grams (option C is correct)
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