Ask Question
24 December, 21:02

How much total energy must be absorbed by a 150 g sample of ice at 0.0°C that it melts

AND then warms to 25.0°C? (Break it into steps and add them together, phase change

and temperature change)

+1
Answers (1)
  1. 24 December, 23:27
    0
    The answer to your question is Qt = 15750 cal

    Explanation:

    Data

    mass = m = 150 g

    Initial temperature = T1 = 0°C

    Final temperature = T2 = 25°C

    Process

    1. - Calculate the Latent heat of fusion

    Latent heat of fusion for water = l = 80 cal/g

    Heat = Q

    Formula

    Q = ml

    Substitution

    Q = (150) (80)

    Simplification and result

    Q = 12000 cal

    2. - Calculate the Specific heat

    Specific heat of water = C = 1 cal/g°C

    Formula

    Q = mCΔT

    Substitution

    Q = (150) (1) (25 - 0)

    Simplification and result

    Q = 3750 cal

    3. - Calculate the total heat

    Qt = 12000 + 3750

    Qt = 15750 cal
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How much total energy must be absorbed by a 150 g sample of ice at 0.0°C that it melts AND then warms to 25.0°C? (Break it into steps and ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers