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1 March, 21:30

7.55 grams of P4 and 7.55 grams of O2 react according to the following reaction:

P4 + O2--> P4O6

If enough oxygen is available, then the P4O6 reacts further:

P4O6 + O2 - -> P4O10

a. Find the limiting reagent in the formation of P4O10.

b. What mass of P4O10 is produced?

c. What mass of excess reactant remains?

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  1. 2 March, 00:09
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    a) The limiting reactant is O2.

    b) 7.57 grams of P4O10 is produced

    c) 7.53 grams P4O6 remains

    Explanation:

    Step 1: Data given

    Mass of P4 = 7.55 grams

    Mass of O2 = 7.55 grams

    Molar mass of P4 = 123.90 g/mol

    Molar mass of O2 = 32 g/mol

    Step 2: The balanced equations:

    P4 + 3O2-→P4O6

    P4O6 + 2O2 → P4O10

    Step 3: Calculate moles P4

    Moles P4 = mass P4 / molar mass P4

    Moles P4 = 7.55 grams / 123.90 g/mol

    Moles P4 = 0.0609 moles

    Step 4: Calculate moles O2

    Moles O2 = 7.55 grams / 32.0 g/mol

    Moles O2 = 0.236 moles

    Step 5: Calculate the limiting reactant

    For 1 mol P4 we need 3 moles O2 to produce 1 mol P4O6

    P4 is the limiting reactant. It will completely be consumed. (0.0609 moles)

    O2 is in excess. There will react 3*0.0609 = 0.1827 moles

    There will remain 0.236 - 0.1827 = 0.0533 moles O2

    Step 6: Calculate moles P4O6

    For 1 mol P4 we need 3 moles O2 to produce 1 mol P4O6

    For 0.0609 moles P4 we will have 0.0609 moles P4O6

    Step 7: Calculate limting reactant

    There remain 0.0533 moles O2 and there are 0.0609 moles P4O6 produced

    For 1 mol P4O6 we need 2 moles O2 to produce 1 mol P4O6

    The limiting reactant is O2. It will completely be reacted (0.0533 moles)

    There will react 0.0533/2 = 0.02665 moles

    There will remain 0.0609 - 0.02665 = 0.03425 moles P4O6

    This is 0.03425 moles * 219.88 g/mol = 7.53 grams P4O6

    Step 8: Calculate moles P4O10

    For 1 mol P4O6 we need 2 moles O2 to produce 1 mol P4O6

    For 0.0533 moles O2, we'll have 0.0533/2 = 0.02665 moles P4O10

    Step 9: Calculate mass P4O10

    Mass P4O10 = 0.02665 moles * 283.89 g/mol

    Mass P4O10 = 7.57 grams
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