What volume does 0.87mol of H2O (g) occupy 36.2oC and 1.25 atm?

A

2.06L

B

17.6L

C

37.1L

D

317L

The answer is 17.66 L of volume occupy by water

Explanation:

According to ideal gas equation, the volume is calculated

PV = nRT

where V = volume

P = Pressure =.

n = number of moles,

T = temperature

Where R = 0.08206 L atm mol-1K-1 is constant

Convert the temperature value from degree centigrade to kelvin 1 °C = 273.15 K

By putting the values in the above equation as we have to find the volume so by adjusting

V = nRT / P n = 0.87 mol P = 1.25 atm T = 36.2 °C = 309.35 K

V = (0.87mol) x (0.08206 L atm mol-1K-1) x (309.3 K) / 1.25 atm

V = 22.08 L atm / 1.25 atm

Volume = 17.66 L