Write the concentration equilibrium constant expression for this reaction. 3I2 (s) + 2Cr3 + (aq) + 7H2O (l) = Cr2O2-7 (aq) + 6I - (aq) + 14H + (aq)

Kc = [Cr₂O₇²⁻].[I⁻]⁶.[H⁺]¹⁴/[Cr³⁺]²

Explanation:

Let's consider the following balanced equation.

3 I₂ (s) + 2 Cr³⁺ (aq) + 7 H₂O (l) = Cr₂O₇²⁻ (aq) + 6 I⁻ (aq) + 14 H⁺ (aq)

The concentration equilibrium constant (Kc) is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species (not liquids or solids).

Kc = [Cr₂O₇²⁻].[I⁻]⁶.[H⁺]¹⁴/[Cr³⁺]²