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10 October, 15:51

Coal containing 15.0% H2O, 2.0% S and 83.0% C by mass is burnt with the stoichiometric amount of air in a furnace. What is the mole fraction of SO2 (g) in the exhaust

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  1. 10 October, 17:53
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    This is a coal combustion process and we will assume

    Inlet coal amount = 100kg

    It means that there are

    15kg of H2O, 2kg of Sulphur and 83kg of Carbon

    Now to find the mole fraction of SO2 (g) in the exhaust?

    Molar mass of S = 32kg/kmol

    Initial moles n of S = 2/32 = 0.0625kmols

    Reaction: S + O₂ = SO₂

    That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂

    Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust

    The mole fraction of SO2 (g) in the exhaust=0.0625kmols
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