1f 3.8 kcal is released by combustion of each gram of

glucose, how many kilocalories are released by the

combustion of 1.50 mol of glucose?

1026.88 kilocalories are released by the combustion of 1.50 mol of glucose

Explanation:

First we have to calculate the amount in grams in 1.5 moles of glucose by using formula

Molecular mass of glucose is 180.156 g/mol

Mass in grams = Molarity x Molecular mass

=1.50 moles x 180.156 g/mol

= 270.23 g

Now we will calculate the amount of energy released

Energy released by 1 gram of glucose = 3.8 Kcal

Energy released by 270.23 gram of glucose = 3.8 x 270.23 Kcal

= 1026.88 Kcal

1026.88 kilocalories are released by the combustion of 1.50 mol of glucose