Ask Question
8 February, 04:18

Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.

Electronegativity difference of Na and F:

yes

no

+2
Answers (2)
  1. 8 February, 05:53
    0
    Yes

    Explanation:

    Electronegativity value of Flourine (F) = 3.98

    Electronegativity value of Sodium (Na) = 0.93

    Electronegativity difference = 3.98 - 0.93 = 3.05

    Since the electronegativity difference is greater than 1.5, it means the bond formed would be an ionic bond.
  2. 8 February, 07:33
    0
    Yes. They will form an ionic bond.

    Explanation:

    Electronegativity of fluorine is 4 and of sodium is 0.9 so

    the difference is 4 - 0.9 = 3.1.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers