When the piston in the Boyle's Law apparatus is at rest, what is the relationship between the pressure of the trapped gas and the pressure on the outside of the piston?

Question

Chemistry

Deon Pena

12 March, 08:32

When the piston in the Boyle's Law apparatus is at rest, what is the relationship between the pressure of the trapped gas and the pressure on the outside of the piston?

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Answers (2)

Know the Answer?

Avery Bender · Answer 1

Pressure of the trapped gas and the pressure on the outside on the piston are the same.

Explanation:

When the piston is at rest, then it exist a mechanical equilibrium, that is to say, that pressure of the trapped gas is equal to the pressure on the outside of the piston.

Eric Brennan · Answer 2

Check the last paragraph in the Explanation section.

Explanation:

In order to understand the Behavior of gases that is how ideal gases and real gases behave, scientists proposed several laws and one of them is the Boyle's Law. The Boyle's Law states that at a constant temperature the pressure of a given mass of an ideal gas is inversely proportional to its volume. The Boyle's Law can be represented mathematically by using the equation below;

PV = k. Where P = pressure, V = volume and k = constant.

Hence, P1V1 = P2V2.

When the piston in the Boyle's Law apparatus is at rest, the area of the Piston would be multiplied by the pressure of the trapped gas which will give the balanced weight. It will also balanced the additional weight.