1 pts

What is the molarity when 8.4 grams of NaF (molar mass = 42 grams/mol) is placed in 100

ml of water?

molarity = 2 mol / L

Explanation:

We know that molarity is equal to the number of moles of solute divided by volume of solution in litter.

Given dа ta:

mass of NaF = 8.4 g

molar mass of NaF = 42 g/mol

volume of water = 100 mL

First of all we will convert the milliliter of solution in to litter.

we know that 1 litter is equal to 1000 mL.

100 / 1000 = 0.1 L

Formula:

molarity = moles / volume in litter

Now we will calculate the number of moles.

number of moles = mass / molar mass

number of moles = 8.4 g / 42 g/mol

number of moles = 0.2 mol

By putting the values in molarity formula, we will get,

molarity = 0.2 mol / 0.1 L

molarity = 2 mol / L