The temperature of the cooling water as it leaves the hot engine

of a certain automobile is 244°F. After it passes through the

radiator it has a temperature of 177°F. Calculate the amount of

heat (in kJ) transferred from the engine to the surroundings by

one gallon of water with a specific heat of 4.1801

J/g.°C. (Assume the density of water is 0.997 g/mL across the

temperature range.)

Q = 5.8 * 10²KJ

Explanation:

Given dа ta:

Initial temperature = 177 °F (80.5556 °C)

Final temperature = 244 °F (117.778 °C)

Mass of water = 1 gal = 3785.41 g

Specific heat of water = 4.1801 J/g.°C

Amount of heat transfer from engine to surrounding = ?

Solution:

ΔT = T2 - T1

ΔT = 117.778 °C - 80.5556 °C = 37.2224 °C

Formula

Q = m. c. ΔT

Q = 3785.41 g * 4.1801 J/g.°C * 37.2224 °C

Q = 588984.64 J

Q = 588.985 KJ

Q = 5.8 * 10²KJ