In a laboratory experiment, after purification, 4.567 g of nickel metal was obtained by a student. The student then calculated, based on the amount of reactants used, that 5.731 g were possible. What is the student's percent yield?

Question

Chemistry

Makai Conway

12 March, 01:28

In a laboratory experiment, after purification, 4.567 g of nickel metal was obtained by a student. The student then calculated, based on the amount of reactants used, that 5.731 g were possible. What is the student's percent yield?

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Answers (2)

Know the Answer?

Martha Callahan · Answer 1

Percent Yield is 79.68%

Explanation:

Since the ideal amount of reactant that was possible is 5.731 g and it experimentally produced 4.567 g, thus its percent yield is given as:

Percent Yield = (Experimental Mass / Theoretical Mass) x 100%

Percent Yield = (4.567 g/5.731g) x 100%

Percent Yield = 79.68%

Reece Bridges · Answer 2

The yield of the purification is 79.7%

Explanation:

Hi there!

5.731 g nickel metal could be produced by the student if the yield of the purification would be 100%. Instead, 4.567 g was obtained. Then, the yield of the purification can be calculated as follows:

4.567 g Ni · (100% / 5.731 g) = 79.7%

The yield of the purification is 79.7%

Have a nice day!