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23 January, 18:37

A 3.2 liter sample of a gas is at 40 oC and 1.0 atmosphere of pressure. If the temperature decreases to 20 oC and the pressure decreases to 0.60 atmospheres, what is the new volume of the gas in liters?

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  1. 23 January, 21:54
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    V₂ = 5 L

    Explanation

    According to general gas equation:

    P₁V₁/T₁ = P₂V₂/T₂

    Given dа ta:

    Initial volume = 3.2 L

    Initial pressure = 1 atm

    Initial temperature = 40 °C (40 + 273 = 313 K)

    Final temperature = 20°C (20+273 = 293 K)

    Final pressure = 0.60 atm

    Final volume = ?

    Solution:

    P₁V₁/T₁ = P₂V₂/T₂

    V₂ = P₁V₁ T₂ / T₁ P₂

    V₂ = 1 atm * 3.2 L * 293 K / 313 K * 0.60 atm

    V₂ = 937.6 atm. L. K / 187.8 K. atm

    V₂ = 5 L
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