Dont understand the answer in simple terms.

Suppose a bag of ice (450g) at 0.0°C sat on a counter and began to melt to liquid water. How much energy must be absorbed by the ice if 2/3 of it melted

100200 j

Explanation:

Given dа ta:

Mass of ice = 450 g

Temperature = 0.0 °C

Mass of ice melted = 2/3 part g 450 g

Energy required = ?

Solution:

Mass of ice melted = 2/3*450 g

Mass of ice melted = 300 g

Heat of fusion = 334 j

Heat absorbed by 300 g:

300 g * 334 j / 1 g

100200 j