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25 May, 23:42

Potassium hydroxide reacts with sulfuric acid how much potassium sulfate is produced from

10.75 g of sulfuric acid

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Answers (1)
  1. 26 May, 03:30
    0
    19 g of K₂SO₄ was produced.

    Explanation:

    2 KOH + H₂SO₄ →K₂SO₄ + 2 H₂O

    Now if we have 10.75 g of H₂SO₄ we can calculate the number of moles as,

    Wt / M. wt = 10.75 / 98 = 0.109 moles

    Now we can calculate the number of moles of K₂SO₄ as that:

    1 mole of H₂SO₄react gives 1 mole K₂SO₄

    0.109 mole of H₂SO₄ gives (x)

    x (number of moles of K₂SO₄ = 1 * 0.109 / 1 = 0.109 mole

    now we can calculate the wt as,

    wt = no. moles * M. wt

    wt = 0.109 * 174.259 = 18.966 g = 19 g
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