What volume of 20 mg/L dye would be required to make 50. mL of. 10 mg/L dye?

The volume required is 25 mL.

Explanation:

Given dа ta:

Volume taken form stock solution to make new solution = V1 = ?

Concentration of stock solution = C1 = 20 mg / L

Concentration of new solution = C2 = 10 mg / L

Final volume of new solution = V2 = 50 mL

Formula:

C1V1 = C2V2

V1 = C2V2 / C1

Now we will put the values in formula,

V1 = (10 mg / L * 50 mL) / 20 mg / L

V1 = (500 mg / L. mL) / 20mg / L

V1 = 25 mL