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19 July, 11:33

Determine the approximate amount of potassium hydrogen phthalate, KHP, that you will need to neutralize 6.00 ml of 0.100 M NaOH. The formula weight of KHP is 204.233 g/mol. If you record this in your laboratory notebook before lab, it will save time in lab.

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  1. 19 July, 13:30
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    potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol

    to get 1000 ml

    Molar concentration = Mass concentration/Molar Mass

    mass concentration = molar concentration x molar mass

    mass concentration=0.1 M,

    molar mass = 204.233 g/mol

    so to get 1L

    mass conc = 204.233 x 0.1

    = 20.4233g for 1L or 1000 ml

    to get 6.00 ml

    if 20.4233g is for 1000ml

    then to 6.00 ml

    = 20.4233 x 6 / 1000

    = 0.123g for 6.00 ml

    according to the equation below

    NaOH (aq) + KHC8H4O4 (aq) - -> KNaC8H4O4 (aq) + H2O (l)

    number of moles of NaOH is equal to that of KHP

    so the same amount will be needed too, which is

    = 0.123g
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