What is the balanced chemical equation for the galvanic cell reaction expressed using shorthand notation below? Al (s) | Al3 + (aq) || Fe2 + (aq) | Fe (s) What is the balanced chemical equation for the galvanic cell reaction expressed using shorthand notation below? Al (s) | Al3 + (aq) || Fe2 + (aq) | Fe (s) 3 Fe (s) + 2 Al3 + (aq) → 3 Fe2 + (aq) + 2 Al (s) 2 Fe (s) + 3 Al3 + (aq) → 2 Fe2 + (aq) + 3 Al (s) 3 Al (s) + 2 Fe2 + (aq) → 3 Al3 + (aq) + 2 Fe (s) 2 Al (s) + 3 Fe2 + (aq) → 2 Al3 + (aq) + 3 Fe (s)

2Al (s) + 3Fe⁺² (Aq) → 2Al⁺³ (aq) + 3Fe (s)

Explanation:

The shorthand notation first places the oxidation reaction and then the reduction reaction. So, the half-reactions are:

Al (s) → Al⁺³ (aq) + 3e⁻ (Al must lose 3 electrons)

Fe⁺² (Aq) + 2e⁻ → Fe (s) (Fe⁺² must gain 2 electrons)

The total amount of electrons must be equal, so the first equation must be multiplied by 2, and the second by 3:

2Al (s) → 2Al⁺³ (aq) + 6e⁻

3Fe⁺² (Aq) + 6e⁻ → 3Fe (s)

And now they must be summed, which will be the balanced chemical equation:

2Al (s) + 3Fe⁺² (Aq) → 2Al⁺³ (aq) + 3Fe (s)