A sample of nitrogen goes from 21L to 14L and it's pressure increases from 100kPa to 150kPa. The final temperature is 300K. What was the initial temperature in Kelvins?

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Chemistry

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14 June, 01:11

A sample of nitrogen goes from 21L to 14L and it's pressure increases from 100kPa to 150kPa. The final temperature is 300K. What was the initial temperature in Kelvins?

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Addyson · Answer 1

The initial temperature is 300 K (The temperature doesn't change)

Explanation:

Step 1: Data given

Initial volume = 21L

Final volume = 14L

Initial pressure = 100 kPa = 0.986923 atm

Final pressure = 150 kPa = 1.48038 atm

The final temperature = 300K

Step 2: Calculate the initial temperature

Calculate the initial temperature

(P1*V1) / T1 = (P2*V2) / T2

⇒with P1 = the initial pressure = 0.986923 atm

⇒with V1 = the initial volume = 21 L

⇒ with T1 = the initial temperature = ?

⇒with P2 = the final pressure = 1.48038 atm

⇒with V2 = the final volume = 14 L

⇒with T2 = the final temperature = 300 K

(0.986923 * 21) / T1 = (1.48038*14) / 300

T1 = 300 K

The initial temperature is 300 K (The temperature doesn't change)