Calculate to three significant digits the density of carbon monoxide gas at exactly - 5c and 1 atm exactly. You can assume carbon monoxide gas behaves as an ideal gas under these conditions.

1.77 g/L.

Explanation:

Molar mass of CO2 = 12 + (16*2)

= 44 g/mol.

Using ideal gas equation,

V/n = R*T/P

Where,

R = 0.082 L. atm/mol. K

T = 30°C

= 273 + 30

= 303 K

P = 1 atm

V/n = (0.082 * 303) / 1

= 24.845 L/mol

Density = mass * volume

Density = molar volume/molar mass

= 44/24.845

= 1.77 g/L