How many atoms are in 52.3 g of lithium hypochlorite (LiClO) ?

1.62 * 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

Explanation:

To find the amount of atoms that are in 52.3 g of lithium hypochlorite, we must first find the amount of moles. We do this by dividing by the molar mass of lithium hypochlorite.

52.3 g : 58.4 g/mol = 0.896 mol

Next we must find the amount of formula units, we do this be multiplying by Avagadro's number.

0.896 mol * 6.02 * 10²³ = 5.39 * 10²³ f. u.

Now to get the amount of atoms we can multiply the amount of formula units by the amout of atoms in one formula unit.

5.39 * 10²³ f. u. * 3 atom/f. u. = 1.62 * 10²⁴ atoms

1.62 * 10²⁴ atoms are in 52.3 g of lithium hypochlorite.