In the gas mixture containing 88 grams of oxygen gas, 88 grams of nitrogen gas, and 12 grams of nitrogen dioxide gas, what is the mole fraction of nitrogen gas?

Answer: The mole fraction of nitrogen = 0.323

Explanation:

Molar Mass of O2 = 32g/mol

Mass of O2 = 88g

nO2 = 88 / 32 = 2.75mol

Molar Mass of N2 = 28g/mol

Mass of N2 = 88g

nN2 = 88 / 28 = 3.14mol

Molar Mass of NO2 = 14 + 32 = 46g/mol

Mass of NO2 = 12g

nNO2 = 46 / 12 = 3.83mol

The mole fraction of nitrogen gas

= nN2 / (nO2 + nN2 + nNO2)

= 3.14 / (2.75 + 3.14 + 3.83)

= 3.14 / 9.72 = 0.323